Answer:
The alcohol concentration of the resulting solution is 58.4%
Step-by-step explanation:
- At first we must to find the quantity of pure alcohol in the 8 liters
∵ The alcohol concentration is 48% in 8 liters
∴ The quantity of pure alcoholic = [tex]\frac{48}{100}*8=3.84[/tex] liters
- She added 2 liters pure alcohol to the solution that means the solution
increased by 2 liters and alcohol quantity increased by 2 liters
∵ She added 2 liters pure alcohol
∴ The quantity of pure alcohol = 2 + 3.84 = 5.84 liters
∴ The resulting solution = 2 + 8 = 10 liters
- Now we need to find the concentration of alcohol in the resulting
solution
∵ The quantity of pure alcohol = 5.84 liters
∵ The resulting solution = 10 liters
∴ The concentrate of alcohol = [tex]\frac{5.84}{10}*100[/tex] % = 58.4%
The alcohol concentration of the resulting solution is 58.4%
Answer:
Alcohol concentration of the resulting solution = 58.4%
Step-by-step explanation:
Maria has added 2 liters of pure alcohol to 8 liters of a 48% alcohol solution.
Volume of alcohol in 8 liters of a 48% alcohol solution is given by
[tex]V_1=\frac{48}{100}\times 8=3.84L[/tex]
New volume of alcohol added by maria, V₂ = 2 L
Total volume of solution, V = 8 + 2 = 10 L
Total volume of alcohol in 10 L solution, Vₐ = V₁ + V₂ = 3.84 + 2 = 5.84 L
[tex]\texttt{Alcohol concentration of the resulting solution =}\frac{\texttt{Total volume of alcohol in 10 L solution}}{\texttt{Total volume of solution}}\times 100\\\\\texttt{Alcohol concentration of the resulting solution =}\frac{5.84}{10}\times 100\\\\\texttt{Alcohol concentration of the resulting solution =}58.4\%[/tex]
Alcohol concentration of the resulting solution = 58.4%
