write the equation in slope intercept form. what are the slope and y intercept?

-5x -12y=11


A: y= -5/12 x + 11/12;slope: -5/12; y-intercept: 11/12

B:y= 5/12 x -11/12;slope: 5/12; y-intercept: -11/12

C:y= -5/12 x - 11/12;slope: -5/12; y-intercept: -11/12

D:y= 5/12 x + 11/12;slope: 5/12; y-intercept: 11/12


need fast please help :)

also if you had answers to unit3 lesson 10 unit test algebra 2 that would be helpful :)

Respuesta :

Option C  

Answer:

The equation in slope intercept form is [tex]-\frac{5}{12} x-\frac{11}{12}[/tex]

The slope is [tex]-\frac{5}{12}[/tex] and y-intercept is [tex]-\frac{11}{12}[/tex]

Solution:

The slope - intercept form equation of line is given as

y = mx + c    ---- eqn(1)

Where m is the slope of the line. The coefficient of “x” is the value of slope of the line.

c is the y – intercept which is the value of y at the point where the line crosses the y-axis

From question, given that -5x - 12y = 11 --- eqn (2)

On converting equation (2) in slope – intercept form, that is adding 5x on both sides,

-5x - 12y + 5x = 5x + 11

-12y = 5x + 11

Now on dividing -12 on both sides,

[tex]y=-\frac{5}{12} x-\frac{11}{12}[/tex]     ---- eqn (3)

Comparing the given equation (3) with equation (1), we get  

[tex]m = -\frac{5}{12}[/tex] and [tex]c = -\frac{11}{12}[/tex]

Hence Option C is correct.