Answer:
60.5 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Equation of motion
[tex]v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-22^2}{2\times -4}\\\Rightarrow s=60.5\ m[/tex]
The distance the car will travel after slamming the brakes is 60.5 m
The car is 100-60.5 = 39.5 away from the stationary car
