Answer:
Frequency change by a factor of 2.
(b) is correct option.
Explanation:
Given that,
Mass = 16 kg
Replaced mass = 4 kg
We need to calculate the frequency
Using formula of frequency
[tex]f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}[/tex]
Put the value into the formula
[tex]f_{1}=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{16}}[/tex]
[tex]f_{1}=\dfrac{1}{2\pi}\dfrac{\sqrt{k}}{4}}[/tex]....(I)
[tex]f_{2}=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{4}}[/tex]
[tex]f_{2}=\dfrac{1}{2\pi}\dfrac{\sqrt{k}}{2}}[/tex]...(II)
[tex]f_{2}=2f_{1}[/tex]
Hence, Frequency change by a factor of 2.
