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What is the magnitude and direction of the electric force on the electron in a uniform electric field of strength 1920 N/C that points in the direction parallel to the y-axis?

Respuesta :

Answer: 30 fN ( 30* 10^-15 N) and it is pointed to to -y-axis.

Explanation: In order tosolve this question we have to usethe Coulomb force given by:

F=e*E= 1.6 *10^-19 C* 1920 N/C= 30 fN the force pints in opossite direction of the electric field due to the sign of charge of the electron.

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