Answer:
Explanation:
given,
cyclist ride 6.2 km east and then 9.28 km in the direction of 27.27° west of north and then 7.99 km west.
vertical component = 9.28 cos∅
= 9.28 cos 27.27°
= 8.24 km
horizontal axis component = 9.28 sin ∅
= 9.28 sin 27.27°
= 4.5 km
distance of the final point from the origin
= 7.99 -(6.2-4.5)
= 6.29 km
displacement
[tex]d = \sqrt{6.29^2+8.24^2}[/tex]
d = 10.37 km
b) [tex]tan \theta = \dfrac{6.29}{8.24}[/tex]
θ = 37.36°
