Answer:
Acceleration of car A is greater than the acceleration of car B
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
Equation of motion
[tex]v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{\frac{65}{2.237}-0}{10}\\\Rightarrow a=2.9\ m/s^2[/tex]
[tex]v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{\frac{65}{2.237}-0}{12}\\\Rightarrow a=2.42\ m/s^2[/tex]
Hence, the acceleration of car A is greater than the acceleration of car B
