A car is going south on I-69 at 33 m/s (74 mph). The car has good brakes so its maximum braking acceleration is – 8.5 m/s^2 . Traffic has come to a stop in all lanes 120 m ahead. What is the maximum reaction time the driver can have and still be able to stop in the available distance? Hint: During the driver’s reaction time, the car continues to have the initial velocity of 33 m/s.

Respuesta :

Answer:

1.69515 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

[tex]v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-33^2}{2\times -8.5}\\\Rightarrow s=64.06\ m[/tex]

The distance between the traffic and the car after braking is 120-64.06 = 55.94 m

Time = Distance / Speed

[tex]\text{Time}=\frac{55.94}{33}\\\Rightarrow \text{Time}=1.69515\ seconds[/tex]

The reaction time cannot be more than 1.69515 seconds