Answer:
Acceleration will be [tex]a=-6.2331cm/sec^2[/tex]
Explanation:
We have given speed of the moving object u = 11 cm /sec
As the object move from +2.79 x -coordinate to -5 x- coordinate
So total distance = 5+2.79 = 7.79 cm
Time is given as t = 2.55 sec
We have to find the acceleration
From second equation of motion we know that [tex]s=ut+\frac{1}{2}at^2[/tex]
[tex]7.79=11\times 2.55+\frac{1}{2}\times a\times 2.55^2[/tex]
[tex]a=-6.2331cm/sec^2[/tex]
