Answer:
178.67hectare[/tex] of land
Explanation:
Total number of days in July and august = 31+31 = 62 days
We have given that 3000 liters of water available for every min, so total water availability for specific 62 will be
= 3000×60×24×62
= 267840000 liters
We know that 1 liters = [tex]10^6mm^3[/tex]
So 267840000 liters = [tex]2.68\times 10^{14}mm^3[/tex] of water
But per hectare of land requires 150 mm of water to get optimal yields, since 1 Hectare =1×[tex]10^{10}[/tex] [tex]mm^2[/tex]
so, each Hectare of land filled with 150 mm of water would have a volume of =[tex]150\times 10^{10}=1.5\times 10^{12}mm^3[/tex]
finally, as 1 Hectare of land needs [tex]1.5\times 10^{12}mm^3[/tex] of water to get desired yields. therefore with [tex]2.68\times 10^{14}mm^3[/tex] volume of water available , total hectares of land which can be planted in corn will be = [tex]\frac{2.68\times 10^{14}mm^3}{1.5\times 10^{12}mm^3}=178.67hectare[/tex]