Answer:
The charge is [tex]2.75\times10^{-13}\ C[/tex]
Explanation:
Given that,
Distance = 2.5 mm
Electric field = 800 NC
Length [tex]L=5.0\times5.0\times10^{-4}\ m[/tex]
We need to calculate the linear charge density
Using formula of linear charge density
[tex]E=\dfrac{2k\lambda}{r}[/tex]
[tex]\lambda=\dfrac{Er}{2k}[/tex]
Put the value into the formula
[tex]\lambda=\dfrac{800\times2.5\times10^{-3}}{2\times9\times10^{9}}[/tex]
[tex]\lambda=1.1\times10^{-10}\ C/m[/tex]
We need to calculate the charge
Using formula of charge
[tex]Q=\lambda\timesL[/tex]
Put the value into the formula
[tex]Q=1.1\times10^{-10}\times(5.0\times5.0\times10^{-4})[/tex]
[tex]Q=2.75\times10^{-13}\ C[/tex]
Hence, The charge is [tex]2.75\times10^{-13}\ C[/tex]
