Answer:
[tex]\frac{mo}{mi} = 2.34[/tex]
Explanation:
Given data:
exhaust velocity = 2.455 km/s
specific impulse = 294 second
[tex]\Delta V = Ve ln\frac{mo}{mi}[/tex]
[tex]\Delta v = velocity[/tex]
Ve = effective exhaust velocity
[tex]Ve = Isp\time s g_0[/tex]
Isp specific impulse
g_o = standard gravity
[tex]vE = 294 \times 9.8 = 2881.2 m[/tex]
from above equation we have
[tex]\frac{mo}{mi} = e^{\frac{\Delta v}{Ve}
[tex]\frac{mo}{mi} = e^{\frac{2455}{2881.2}[/tex] [ 2.455 km/s = 2455 m/s]
[tex]\frac{mo}{mi} = 2.34[/tex]
