Answer:
4.11 m/s
Explanation:
Given:
v₀ₓ = 1.25 m/s
aₓ = 0 m/s²
v₀ᵧ = 0 m/s
aᵧ = -9.8 m/s²
t = 0.4 s
Find: v
First, in the x direction:
vₓ = aₓt + v₀ₓ
vₓ = (0 m/s²) (0.4 s) + 1.25 m/s
vₓ = 1.25 m/s
And in the y direction:
vᵧ = aᵧt + v₀ᵧ
vᵧ = (-9.8 m/s²) (0.4 s) + 0 m/s
vᵧ = -3.92 m/s
The net speed is found with Pythagorean theorem:
v² = vₓ² + vᵧ²
v² = (1.25 m/s)² + (-3.92 m/s)²
v = 4.11 m/s