Answer:
53.29% of acetic acid is Oxygen
Explanation:
Step 1: Given data
Acetic acid it's molecular formula is HC2H3O2. This means it consists of 3 elements Carbon, Hydrogen and oxygen.
Step 2: the molar masses
The molecular mass of acetic acid is:
4* H = 4* 1.01 g/mole
2* C = 2*12 g/mole
2*O = 2* 16 g/mole
Total molar mass = 4+ 24+32 = 60.052 g/mole
Step 3: Calculate the mass percent
32 g of the 60.052 g is Oxygen
(32/60.052) *100% = 53.29%
53.29% of acetic acid is Oxygen.
Answer:
The mass percent composition is 53.2852 %
Explanation:
The formula used to calculate the % composition is
% composition = (mass of the element)/(total mass of the compound) × 100%
Total mass of the compound [tex]C_2H_4O_2[/tex]
= (12.0107 × 2) + (1.0079 × 4) + (15.999 × 2)
= 24.02140 + 4.03176 + 31.99880
= 60.05196 g
Mass of the element, O = 31.99880 g
% composition of O
= (mass of the element) / (total mass of the compound) × 100%
Plugging into the formula
% composition of O
[tex]=\frac {31.99880g}{60.05196g} \times 100 \\\\[/tex]
= 53.2852 % (Answer)
