The moist density for this moist soil sample is equal to 1958.3 [tex]Kg/m^3[/tex].
Given the following data:
- Total volume, V = 1.2 [tex]m^3[/tex].
- Moisture content, w = 8.6% = 0.086
- Specific gravity of soil solids, GS = 2.71.
How to determine the moist density.
Mathematically, moist density is given by this formula:
[tex]\rho_{moist}=\frac{Total\;mass}{Total\;volume} \\\\\rho_{moist}=\frac{2350}{1.2}[/tex]
Moist density = 1958.3 [tex]Kg/m^3[/tex].
How to determine the dry density.
First of all, we would calculate the mass of dry soil by using this expression:
[tex]w=\frac{Total\;mass-Mass\;of\;dry\;soil}{Mass\;of\;dry\;soil} \\\\0.086=\frac{2350-Mass\;of\;dry\;soil}{Mass\;of\;dry\;soil}\\\\0.086(Mass\;of\;dry\;soil)=2350-Mass\;of\;dry\;soil\\\\0.086(Mass\;of\;dry\;soil)+Mass\;of\;dry\;soil=2350\\\\1.086(Mass\;of\;dry\;soil)=2350\\\\Mass\;of\;dry\;soil=\frac{2350}{1.086} \\\\Mass\;of\;dry\;soil=2,163.904\;kg[/tex]
Mathematically, dry density is given by this formula:
[tex]\rho_{moist}=\frac{2,163.904}{1.2} \\\\\rho_{moist}=\frac{2350}{1.2}[/tex]
Dry density = 1,803.3 [tex]Kg/m^3[/tex].
How to determine the void ratio.
First of all, we would find the volume of voids in the soil sample:
[tex]V_s=\frac{Mass\;of\;dry\;soil}{G_s\rho_w} \\\\V_s=\frac{2163.904}{2.71 \times 1000} \\\\V_s=0.7985\;m^3[/tex]
Mathematically, void ratio is given by this formula:
[tex]e=\frac{V_v}{V_s} =\frac{Total\;volume - V_s}{V_s}\\\\e=\frac{1.2 - 0.7985}{0.7985}[/tex]
e = 0.5028.
How to determine the porosity.
Mathematically, porosity is given by this formula:
[tex]n=\frac{e}{1+e} \\\\n=\frac{0.5028}{1+0.5028} \\\\n=\frac{0.5028}{1.5028}[/tex]
n = 0.3346.
How to determine the degree of saturation.
Mathematically, degree of saturation is given by this formula:
[tex]S_r=\frac{wG_s}{e} \\\\S_r=\frac{0.086 \times 2.71}{0.5028}\\\\S_r=0.4635[/tex]
Degree of saturation = 46.35%.
For the volume of water in the soil:
[tex]V_w=\frac{Total\;mass-Mass\;of\;dry\;soil}{\rho_w} \\\\V_w=\frac{2350-2163.904}{ 1000} \\\\V_w=0.1861\;m^3[/tex]
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