Answer:
The system [tex]6x-5y=7\\12x-10y=14[/tex] has infinitely many solutions [tex]x=\frac{5}{6}y +\frac{7}{6}\\y=arbitrary[/tex]
Step-by-step explanation:
We have the following system of equations:
[tex]6x-5y=7\\12x-10y=14[/tex]
The augmented matrix of the system is:
[tex]\left[\begin{array}{cc|c}6&-5&7\\12&-10&14\end{array}\right][/tex]
Transform the augmented matrix to the reduced row echelon form
[tex]\left[\begin{array}{cc|c}1&-5/6&7/6\\12&-10&14\end{array}\right][/tex]
[tex]\left[\begin{array}{cc|c}1&-5/6&7/6\\0&0&0\end{array}\right][/tex]
From the reduced row echelon form of the augmented matrix we have the corresponding system of linear equations:
[tex]x-\frac{5}{6}y=\frac{7}{6}\\0=0[/tex]
The last row of the system (0 = 0) means that the system has infinitely many solutions.
[tex]x=\frac{5}{6}y +\frac{7}{6}\\y=arbitrary[/tex]