Answer and Solution:
For:
(a) [tex](100)_{8}[/tex]
Now,
[tex](100)_{8} = (2^{8})_{10} = (64)_{10}[/tex]
Therefore, the no. preceding is [tex](63)_{10} = (77)_{8}[/tex]
The no. succeeding is [tex](65)_{10} = (101)_{8}[/tex]
(b) [tex](10000)_{5}[/tex]
Now,
[tex]5^{4} = (625)_{10}[/tex]
Therefore, the no. preceding is [tex](624)_{10} = (4444)_{5}[/tex]
The no. succeeding is [tex](626)_{10} = (10001)_{5}[/tex]
(c) [tex](101)_{2}[/tex]
Now,
[tex](101)_{2} = 2^{2}\times 1 + 0\times 2 + 2^{0}\times 1 = (5)_{10}[/tex]
Therefore, the no. preceding is [tex](4)_{10} = (100)_{2}[/tex]
The no. succeeding is [tex](6)_{10} = (110)_{2}[/tex]
