Respuesta :
Answer:[tex]73.05[/tex]
Explanation:
Given
Initial Water Temperature is [tex]20^{\circ}[/tex]
and volume expansion is 2%
Also we know that water volume expansion coefficient is [tex]0.377\times 10^{-3}/K[/tex]
[tex]V=V_0(1+\gamma \Delta T)[/tex]
[tex]\frac{\Delta V}{V}=\gamma \Delta T[/tex]
[tex]0.377\times 10^{-3}\times \Delta T=0.02[/tex]
[tex]\Delta T=\frac{0.02}{0.377\times 10^{-3}}[/tex]
[tex]\Delta =53.05[/tex]
[tex]T_2-20=53.05[/tex]
[tex]T_2=73.05 ^{\circ}[/tex]
Answer:
The max temperature rise in Celsius degrees allowed without jeopardizing safety is [tex]$T_{2}=73.05^{\circ}$[/tex].
Explanation:
The volume expansion of tank is [tex]$2 \%$[/tex].
At [tex]20[/tex] degree Celsius.
[tex]$V=V_{0}(1+\gamma \Delta T)$[/tex]
[tex]$\frac{\Delta V}{V}=\gamma \Delta T$[/tex]
Water volume expansion coefficient : [tex]$0.377 \times 10^{-3} / K$[/tex]
[tex]$0.377 \times 10^{-3} \times \Delta T=0.02$[/tex]
[tex]$\Delta T=\frac{0.02}{0.377 \times 10^{-3}}$[/tex]
[tex]$\Delta=53.05$[/tex]
The temperature is,
[tex]$T_{2}-20=53.05$[/tex]
[tex]$T_{2}=73.05^{\circ}$[/tex]
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