Answer:
34.2 × 10⁻¹¹ J
Step-by-step explanation:
Data provided in the question:
A proton and an antiproton collide
Mass of proton = 1.9 × 10⁻²⁷ kg
Mass of antiproton = 1.9 × 10⁻²⁷ kg
Now,
By Einstein Theory,
The Energy is given as:
E = mc²
Where,
E is the energy
m is the mass
c is the speed of the light = 3 × 10⁸ m/s
Therefore,
The total energy produced = Energy by proton + Energy by antiproton
or
The total energy produced
= 1.9 × 10⁻²⁷ × ( 3 × 10⁸ )² + 1.9 × 10⁻²⁷ × ( 3 × 10⁸ )²
or
= 2 × 1.9 × 10⁻²⁷ × ( 3 × 10⁸ )²
= 3.8 × 10⁻²⁷ × 9 × 10¹⁶
= 34.2 × 10⁻¹¹ J
