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Calculate the diffusive force (J) experienced by K+ in a cell where the concentration gradient is 35 mM, the membrane width is 1 cm, solubility of K+ across the membrane is 1 and the diffusive area (# of channels available) is 10. Assume that the cell is at 1 degree Celsius

J = [(C1-C2)*TSA]/∆X

Respuesta :

Answer:

J = 95.9 mol².K.cm / L²

Explanation:

  • J = [( C1 - C2 )*TSA] / ΔX

∴ C1 - C2 = 35 mM = 0.035 mol/L

∴ ΔX = 1 cm

∴ S = 1 mol/L

∴ A = 10cm²

∴ T = 1°C = 274 K

⇒ J = ( 0.035 mol/L * 274K* 1 mol/L *10 cm² ) / 1 cm

⇒ J = 95.9 mol².K.cm / L²

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