Answer: The molar concentration of ethylenediminediacetic-dihydrate and sodium ions in solution is 0.1976 M and 0.3952 M respectively.
Explanation:
To calculate the molarity of solution, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]
We are given:
Mass of solute (disodium ethylenediaminetetraacetic acid dihydate) = 36.7845 g
Molar mass of disodium ethylenediaminetetraacetic acid dihydate = 372.24 g/mol
Volume of solution = 0.5000 L
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{36.7845g}{372.24g/mol\times 0.5000L}\\\\\text{Molarity of solution}=0.1976M[/tex]
As, 1 mole of disodium ethylenediaminetetraacetic acid dihydate produces 2 moles of sodium ion and 1 mole of ethylenediminediacetic-dihydrate.
Concentration of ethylenediminediacetic-dihydrate in solution = [tex](1\times 0.1976)=0.1976M[/tex]
Concentration of sodium ions in solution = [tex](2\times 0.1976)=0.3952M[/tex]
Hence, the molar concentration of ethylenediminediacetic-dihydrate and sodium ions in solution is 0.1976 M and 0.3952 M respectively.
