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Object A and Object B are two objects in motion. Given the graph of Object A and the equation y = 5/2

x of Object B, which of the two moving objects has greater speed and by what factor? (round to nearest hundredth)

A) Object A by a factor of 1.56

B) Object B by a factor of 1.56

C) Object A by a factor of 1.99

D) Object B by a factor of 1.99

Question

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lilliedunn lilliedunn · Answer 1 · 2019-10-02T18:03:00+02:00

B is the correct sander hope it helps

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slicergiza slicergiza · Answer 2 · 2019-10-20T14:23:28+02:00

Answer:

B) Object B by a factor of 1.56

Step-by-step explanation:

Given,

The equation that shows the motion of the object B,

[tex]y=\frac{5}{2}x[/tex],

Also, the graph shows the motion of object A,

By the graph, the line that shows the motion of object A passes through points (0, 0) and (5,8),

Thus, the equation of the line that shows the motion of object A,

[tex]y - 0 = \frac{8}{5}(x-0)[/tex]

[tex]y = \frac{8}{5}x[/tex]

∵ Slope of line [tex]y=\frac{5}{2}x[/tex] is [tex]\frac{5}{2}[/tex]

And, slope of line [tex]y=\frac{8}{5}x[/tex] is [tex]\frac{8}{5}[/tex],

Since, [tex]\frac{5}{2} > \frac{8}{5}[/tex]

Thus, the object B is has greater speed,

Also,

[tex]\frac{\text{Speed of object B}}{\text{Speed of object A}}=\frac{\frac{5}{2}}{\frac{8}{5}}=\frac{25}{16}=1.5625\approx 1.56[/tex]

I.e. OPTION B is correct.

Note : If a line y = mx passes through (0, 0) shows the motion of an object then m represents its speed.