Answer: The mass of oxygen gas produced is 2.4 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of ammonium perchlorate = 8.84 g
Molar mass of ammonium perchlorate = 117.5 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of ammonium perchlorate}=\frac{8.84g}{117.5g/mol}=0.0752mol[/tex]
The chemical equation for the decomposition of ammonium perchlorate follows:
[tex]2NH_4ClO_4\rightarrow N_2+Cl_2+2O_2+4H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of ammonium perchlorate produces 2 moles of oxygen gas.
So, 0.0752 moles of ammonium perchlorate will produce = [tex]\frac{2}{2}\times 0.0752=0.0752mol[/tex] of oxygen gas
Now, calculating the mass of oxygen gas from equation 1, we get:
Molar mass of oxygen gas = 32 g/mol
Moles of oxygen gas = 0.0752 moles
Putting values in equation 1, we get:
[tex]0.0752mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0752mol\times 32g/mol)=2.4g[/tex]
Hence, the mass of oxygen gas produced is 2.4 grams