Answer:
The speed of the roll is 1239.52 revolutions per minut (1239.52 rpm).
Step-by-step explanation:
In this problem we want to know the angular speed of the roll, knowing its tangencial speed (1220 yards/hour).
The relation between the angular speed and the tangencial speed is
[tex]v=\omega*r=\omega*(D/2)[/tex]
[tex]\omega=2v/D[/tex]
In this case we have a diameter of 3 cm and a velocity of 1220 yards/hour. So we can write
[tex]\omega=2v/D=2*1220\frac{yards}{hour} *\frac{1}{3\,cm} *\frac{91.44cm}{1 yard} *\frac{1hour}{60min}= 1239.52 \frac{1}{min}=1239.52 rpm[/tex]
So the speed of the roll is 1239.52 revolutions per minut (1239.52 rpm).
