Answer:
23 flies
Explanation:
Let true breeding flies with normal wings and gray body : AABB
Let true breeding flies with curved wings and ebony body: aabb
Their cross: AABB X aabb = AaBb ( F1 progeny )
Ratio in F2 progeny when F1 progeny is self crossed ( considering independent assortment)
AaBb X AaBb =
flies with normal wings, gray body: 9
flies with normal wings, ebony body: 3
flies with curved wings, gray body: 3
flies with curved wings, ebony body: 1
Here, 120 flies were collected. According to the ratio of independent assortment number of flies with curved wings and gray body:
(3/16) * 120 = 22.5 = almost 23 flies