A; A dot that represents the box
B; A vector labeled Fg, pointing straight down
E; Avector labeled Fs, pointing parallel to and up the ramp.
This is just about basics of force diagram on an object resting on an inclined plane.
- Now, the first thing we need to do is to draw a dot at the centre of the box as this is where, we will draw the other forces acting on the box.
- Secondly, we need to acknowledge the force of gravity(F_g) which is a vertical vector line drawn from that dot and its' perpendicular component ensures that the box is pressing the inclined plane.
- Thirdly, we see that the box is sliding down the ramp, but it will encounter some resistance from friction in the other direction. Thus, we will draw a vector line from the dot to the left of the box that is parallel to the inclined plane. This line will indicate Frictional force(F_fs).
- Fourthly, there would be a normal force that is trying to counter the perpendicular component of the Force of gravity(F_g). This normal force is directly opposite in direction to the perpendicular component of F_g. This is known as F_g•sin θ. To indicate this normal force, we will draw a vector line perpendicular to the inclined plane starting from the dot. This normal force is indicated by F_n.
Looking at the options, the only ones that correspond with the forces I have listed above and their right position are; Options A, B and E.
Read more at; brainly.in/question/25479972
