Erfan pushes a 5kg crate of stage props starting from rest alongthe smooth and slippery horizontal floor of a theater stage. Thecrate moves with a constant acceleration for 10 seconds as Erfanpushes with a force of 0.22 N to reach the edge of the stage. Thenthe crate runs off the edge of the stage and lands in the orchestrapit below. The floor of the orchestra pit is 3 meters below theedge of the stage. Assume friction is negligible. How far awayfrom the stage edge does the crate land?

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aristocles aristocles · Answer 1 · 2019-10-04T03:07:10+02:00

Answer:

[tex]d = 0.344 m[/tex]

Explanation:

mass of the crate = 5 kg

Force on crate = 0.22 N

[tex]acceleration = \frac{Force}{mass}[/tex]

[tex]acceleration = \frac{0.22}{5}[/tex]

[tex]a = 0.044 m/s^2[/tex]

now the speed of the crate after t = 10 s

[tex]v_f = v_i + at[/tex]

[tex]v_f = 0 + 0.044 \times 10[/tex]

[tex]v_f = 0.44 m/s[/tex]

Now the time taken by the crate to reach the orchestra pit

[tex]y = \frac{1}{2}gt^2[/tex]

[tex]3 = \frac{1}{2}(9.8)t^2[/tex]

[tex]t = 0.78 s[/tex]

now we know that

[tex]d = vt[/tex]

[tex]d = (0.44)(0.78)[/tex]

[tex]d = 0.344 m[/tex]