Respuesta :
Answer:
[tex]\frac{5}{13}[/tex]
Step-by-step explanation:
Given,
Red marbles = 3,
Green marbles = 10,
So, the total marbles = 3 + 10 = 13,
[tex]\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}[/tex]
Since, here replacement is not allowed,
Thus, the probability of getting a green marble and a red marble
= first red and second green + first green second red
[tex]=\frac{3}{13}\times \frac{10}{12}+\frac{10}{13}\times \frac{3}{12}[/tex]
[tex]=2\times \frac{3}{13}\times \frac{10}{12}[/tex]
[tex]=\frac{30}{78}[/tex]
[tex]=\frac{5}{13}[/tex]
Note : The probability of getting a green marble first and a red marble second
= [tex]\frac{10}{13}\times \frac{3}{12}[/tex]
[tex]=\frac{30}{156}[/tex]
[tex]=\frac{5}{26}[/tex]
The probability of getting a green marble and a red marble when picking two marbles from the jar without replacing the first one is; ⁵/₁₃
What is the selection probability?
We are given;
Number of red marbles = 3
Number of green marbles = 10,
Thus,
Total marbles = 3 + 10
Total marbles = 13
Probability of first red and second green is;
P(Red then Green) = (³/₁₃ * ¹⁰/₁₂)
Probability of first green and second red is;
P(green then red) = (¹⁰/₁₃ * ³/₁₂)
Thus, probability of getting a green marble and a red marble is;
P(Green and red) = (³/₁₃ * ¹⁰/₁₂) + (¹⁰/₁₃ * ³/₁₂)
P(Green and red) = ⁵/₁₃
Read more on probability selection at; https://brainly.com/question/251701
