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Suppose that you are running a concession stand when a person gives you $18 and asks for six drinks and as many hot dogs as the remaining money will buy. If drinks are $1.00 and hot dogs are $1.75, what is the maximum number of hot dogs the person can buy? Write an inequality that represents your solution.

Respuesta :

unicorns110504

Answer:

6 hotdogs

Step-by-step explanation:

1.00d + 1.75h <_ (less than or equal to) 18

Now substitute in 6 for d

1.00(6) + 1.75h <_ 18

6.00 + 1.75h <_ 18

-6                        -6

1.75h <_ 12

/1.75        /1.75

h <_ 6.85

We'll round to 6 because you can't have .85 of a hotdog!

Hope this helps!!!

-Unicorns110504

*Please mark brainliest*

Answer: The maximum number of hot dogs that he can buy is 6.

Step-by-step explanation:

Since we have given that

Cost of each drink = $1.00

Cost of each hot dogs = $1.75

Number of drinks = 6

Let the number of hot dogs be 'x'.

Total amount he has = $18

So, the inequality would be

[tex]1\times 6+1.75x\leq 18\\\\6+1.75x\leq 18\\\\1.75x\leq 18-6\\\\1.75x\leq 12\\\\x\leq \dfrac{12}{1.75}\\\\x\leq 6.85[/tex]

So, the number of hot dogs would be atmost 6.

Hence, the maximum number of hot dogs that he can buy is 6.

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