Answer:
4
Explanation:
Given that length of tube,L=1 m
Frequency ,f=653 Hz
We know that
V= f λ
4 L = nλ
So we can say that
[tex]L_n=\dfrac{nV}{4f}[/tex]
Where n is the odd number .
Here V=343 m/s
a)
For n=1:
[tex]L_1=\dfrac{343}{4\times 653}[/tex]
[tex]L_1=0.13\ m[/tex]
For n=3:
[tex]L_3=\dfrac{3\times 343}{4\times 653}[/tex]
[tex]L_3=0.39[/tex]
For n=5:
[tex]L_5=\dfrac{5\times 343}{4\times 653}[/tex]
[tex]L_5=0.65[/tex]
For n=7:
[tex]L_7=\dfrac{7\times 343}{4\times 653}[/tex]
[tex]L_7=0.91[/tex]
So total positions will be 4.