Answer:
x = 4 , y = 6
Step-by-step explanation:
Solve the following system:
{x + 3 y = 22 | (equation 1)
2 x - y = 2 | (equation 2)
Swap equation 1 with equation 2:
{2 x - y = 2 | (equation 1)
x + 3 y = 22 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x - y = 2 | (equation 1)
0 x+(7 y)/2 = 21 | (equation 2)
Multiply equation 2 by 2/7:
{2 x - y = 2 | (equation 1)
0 x+y = 6 | (equation 2)
Add equation 2 to equation 1:
{2 x+0 y = 8 | (equation 1)
0 x+y = 6 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 4 | (equation 1)
0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = 4 , y = 6
