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An object moves at constant speed along a circular path in a horizontal plane, with the center at the origin. When the object is at –2.0 m, its velocity is –(4.0 m/s). In which direction is the object traveling? Clockwise Counterclockwise (b) What is the object’s velocity at 2.0 m?

Respuesta :

Answer:

a)Counterclockwise

b)ω=2 rad/s

Explanation:

Given that

Object at = --2 m

r= - 2 m

Velocity pf object V = - 4 m/s

We know that

[tex]\vec{V}=\vec{\omega }\times \vec{r}[/tex]

r= - 2 i m

V= - 4 j m/s

- 4 j= ω x (- 2 i)

ω  should be in counter clockwise (k) to satisfy the above equation.

It means that the direction of object will in counter clockwise.

4 = ω x 2

ω=2 rad/s

So object velocity at 2 m will be 2 rad/s.

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