Answer:
[tex]u_x=38.13\ m/s[/tex]
Explanation:
Given that initially ball moves in the horizontal direction ,it means that the velocity in the vertical direction is zero.
Horizontal distance = 13 m
Vertical distance = 57 cm
Lets take time to cover 57 cm distance in vertical direction is t.
We know that g is the constant acceleration in the vertical direction so we can apply the equation of motion in the vertical direction.
[tex]S=u_yt+\dfrac{1}{2}gt^2[/tex]
Here [tex]u_y=0[/tex]
S= 57 cm
[tex]0.57=0\times t+\dfrac{1}{2}\times 9.81\times t^2[/tex]
t=0.34 s
Now in the horizontal direction
[tex]x=u_xt[/tex]
Here x=13 m
t= 0.34 s
So
[tex]13=u_x\times 0.34[/tex]
[tex]u_x=38.13\ m/s[/tex]
So the initial speed of ball is 38.13 m/s.
Based on the calculations, the initial speed of this tennis ball is equal to 38.13 m/s.
Given the following data:
Horizontal distance = 13 m
Vertical distance = 57 cm to m = 0.57 m.
In order to determine initial speed of the tennis ball, we would solve for the time taken to travel in the vertical distance by applying the second equation of motion:
S = ut + 1/2at²
0.57 = 0(t) + 1/2 × 9.8 × t²
0.57 = 4.9t²
t = 0.34 seconds.
For the initial speed, we have:
X = ut
u = X/t
u = 13/0.34
u = 38.13 m/s.
Read more on initial speed here: https://brainly.com/question/19365526
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