Respuesta :
Answer:
The right statement is "The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2."
Explanation:
The Beer-Lambert Law states that the absorbance is directly proportional to the concentration of the substance.
Absorbance = εLc
ε: molar absorptivity coeficient
L: optical path length
c: molar concentration
Therefore, if ε and L are the same, the higher the concentration, the higher the absorbance and the lower the transmitance.
Since sample 1 has a higher concentration of CuSO₄ than sample 2, sample 1 has a higher absorbance and lower percent transmittance.
When light passes through to samples of CuSO₄, the percent transmittance of light, %T, will be lower for Sample 1 compared to Sample 2.
CuSO₄ absorbs light strongly at a wavelength of 635 nm. We can measure this process through 2 variables closely related:
- Absorbance: is a measure of the quantity of light absorbed by a sample.
- Transmittance: is the ratio of the light passing through to the light incident on the sample.
We can relate the absorbance (A) of a sample to its concentration (c) through Lambert-Beer's law.
[tex]A = \epsilon \times l \times c[/tex]
where,
- ε: molar absorptivity of the species
- l: length of light path
We can see from this expression, that there is a direct relationship between concentration and absorbance. Thus, sample 1, with a higher concentration, will have a higher absorbance.
On the other hand, we can relate absorbance to percent transmittance (%T) through the following expression.
[tex]\% T = 10^{2-A}[/tex]
As we can see, there is an inverse relationship between absorbance and percent transmittance. Thus, sample 1, with a higher absorbance, will have a lower percent transmittance.
When light passes through to samples of CuSO₄, the percent transmittance of light, %T, will be lower for Sample 1 compared to Sample 2.
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