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An iron ball weighing 10 pounds rests on two smooth plane-surfaced boards that are inclined at respectively 30 and 60 to the horizontal. To the nearest whole number, what is the pressure on the board from F1?

Respuesta :

carlosfuentest

Answer:

F1=9 lb.; F2= 5lb.

Step-by-step explanation:

F1 =10 lb.* Cos (30°) = 10lb.*(0,866) = 8,66 lb. ≈ 9 lb.

F2 =10 lb.* Cos (60°) = 10lb.*(0,5) = 5 lb.

obasola1

Answer:

a.8.66N

b. 5N

Step-by-step explanation:

An iron ball weighing 10 pounds rests on two smooth plane-surfaced boards that are inclined at respectively 30 and 60 to the horizontal. To the nearest whole number, what is the pressure on the board from F1?

Assumption: the iron ball's mass in real sense is 10 pounds

we resolved the weight to horizontal components by taking cosine of an angle. it is inclined at 30 and 60 deg respectively.

therefore

F1=10cos30

F2=10cos60

F1=10[tex]\sqrt{3} /2[/tex]=[tex]5\sqrt{3}[/tex]N=8.66N

F2=10*0.5=5N

Note: the pressure cant be calculated  because we do not know the area the ball covers on the ground

Recall that pressure is actually force per unit area.

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