Respuesta :
Answer:
We can use the criss-cross method to work out the formulas.
Explanation:
The steps are
- Write the symbols of the anion and cation.
- Criss-cross the numbers of the charges to become the subscripts of the other ion.
- Write the formula with the new subscripts.
- Divide the subscripts by their highest common factor.
- Omit all subscripts that are 1.
When we use this method, the formula for the compound formed from NH₄⁺ and PO₄³⁻ becomes (NH₄)₃PO₄.
The table below lists the formulas for the possible combinations.
[tex]\begin{array}{ccc}& \textbf{PO}_{4}^{3-} & \textbf{ClO}_{3}^{-}\\\textbf{NH}_{4}^{+} & \text{(NH$_{4}$)$_{3}$PO$_{4}$} & \text{NH$_{4}$ClO}_{3}\\\textbf{Fe}^{3+} & \text{FePO}_{4} & \text{Fe(ClO$_{3}$)}_{3}\\\end{array}[/tex]
Empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound. Ionic compounds is formed when the complete transfer of electrons takes place from one element (usually metals) or group of atoms (polyatomic positive ions) to another element (usually non-metals) or group of atoms (polyatomic negative ions).
To form the ionic compounds of the given ions, we must combine a positive and a negative ion together.
- When [tex]NH_4^+[/tex] combines with [tex]PO_4^{3-}[/tex], it produces an ionic compound that has a chemical formula of [tex](NH_4)_3PO_4[/tex]. Here 3 molecules of [tex]NH_4^+[/tex] combines with 1 molecule of [tex]PO_4^{3-}[/tex].
- When [tex]NH_4^+[/tex] combines with [tex]ClO_3^{-}[/tex], it produces an ionic compound that has a chemical formula of [tex]NH_4ClO_3[/tex]. Here 1 molecule of [tex]NH_4^+[/tex] combines with 1 molecule of [tex]ClO_3^{-}[/tex].
- When [tex]Fe^{3+}[/tex] combines with [tex]PO_4^{3-}[/tex], it produces an ionic compound that has a chemical formula of [tex]FePO_4[/tex]. Here 1 mole of [tex]Fe^{3+}[/tex] combines with 1 molecule of [tex]PO_4^{3-}[/tex].
- When [tex]Fe^{3+}[/tex] combines with [tex]ClO_3^{-}[/tex], it produces an ionic compound that has a chemical formula of [tex]Fe(ClO_3)_3[/tex]. Here 1 mole of [tex]Fe^{3+}[/tex] combines with 3 molecules of [tex]ClO_3^{-}[/tex].
Thus, the ionic compounds formed are [tex](NH_4)_3PO_4, NH_3ClO_3, FePO_4\text{ and }Fe(ClO_3)_3[/tex]
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