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A supply bag is dropped from a rescue plane. After the bag falls for 3.2 seconds, what is the velocity of the bag?
How far has the bag fallen?

I know the answer to the first one is -19.6 but im struggling to figure out the second

Respuesta :

MathPhys

Answer:

-31.4 m/s

50.2 m

Explanation:

Given:

x₀ = 0 m

v₀ = 0 m/s

t = 3.2 s

a = -9.8 m/s²

Find: v and x

v = at + v₀

v = (-9.8 m/s²) (3.2 s) + 0 m/s

v = -31.36 m/s

x = x₀ + v₀ t + ½ at²

x = 0 m + (0 m/s) (3.2 s) + ½ (-9.8 m/s²) (3.2 s)²

x = -50.176 m

Rounding, the bag reaches a velocity of -31.4 m/s after falling a distance of 50.2 m.

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