Answer:
Electric field, [tex]E=6.86\times 10^6\ N/C[/tex]
Explanation:
It is given that,
Mass of sphere, m = 2.1 g = 0.0021 kg
Charge, [tex]q=-3\ nC=-3\times 10^{-9}\ C[/tex]
We need to find the magnitude of electric field that balances the weight of a plastic spheres. So,
[tex]ma=qE[/tex]
a = g
[tex]E=\dfrac{mg}{q}[/tex]
[tex]E=\dfrac{0.0021\ kg\times 9.8\ m/s^2}{-3\times 10^{-9}\ C}[/tex]
[tex]E=6860000\ N/C[/tex]
or
[tex]E=6.86\times 10^6\ N/C[/tex]
Hence, the magnitude of electric field that balances its weight is [tex]6.86\times 10^6\ N/C[/tex]. Hence, this is the required solution.
