Use the table below to answer the questions that follow.

Thermodynamic Quantities for Selected Substances at 298.15 K (25°C)
Substance ΔH°f (kJ/mol) ΔG°f (kJ/mol) ΔS (J/K-mol)
Carbon
C (s, diamond) 1.88 2.84 2.43
C (s, graphite) 0 0 5.69
C2H2 (g) 226.7 209.2 200.8
C2H4 (g) 52.30 68.11 219.4
C2H4 (g) -84.68 -32.89 229.5
CO (g) -110.5 -137.2 197.9
CO2 (g) -393.5 -394.4 213.6

Hydrogen
H2( g) 0 0 130.58

Oxygen
O2 (g) 0 0 205.0
H2O (l) -285.83 -237.13 69.91


The value of ΔS° for the catalytic hydrogenation of ethene to ethane, C2H4 (g) H2(g) → C2H6 (g)

Respuesta :

Answer:

The value of ΔS° for the catalytic hydrogenation of ethene to ethane is -120,48 J K⁻¹ mol⁻¹.

Explanation:

The ΔS° of a reaction is:

ΔS°= S (products) - S (reactants)

The only product is ethane (with S°= 229,5 J K⁻¹ mol⁻¹).

Reactants are ethene and H₂ (g) (with S°= 219,4 J K⁻¹ mol⁻¹ and S°= 130,58 J K⁻¹ mol⁻¹, respectively)

So, ΔS° is:

ΔS°= 229,5 J K⁻¹ mol⁻¹ - (219,4 J K⁻¹ mol⁻¹ +  130,58 J K⁻¹ mol⁻¹)

ΔS°= -120,48 J K⁻¹ mol⁻¹

I hope it helps!