Answer:
the correct answer is option A
Explanation:
given,
Load = 6000 lbf
depth = 3.5 ft
distance from the load = 4 ft
vertical stress = [tex]\dfrac{3Pz^3}{2\pi (r^2+z^2)^{\frac{5}{2}}}[/tex]
= [tex]\dfrac{3\times 6000\times 3.5^3}{2\pi (4^2+3.5^2)^{\frac{5}{2}}}[/tex]
= 28.96 lbf/ft²
= 29 lbf/ft²
hence, the correct answer is option A