Respuesta :
Answer:
Total number of electrons
[tex]N = 7.25 \times 10^{24}[/tex]
electrons removed from each sphere
[tex]N = 5.27 \times 10^{15}[/tex]
Fraction of electrons transferred is given as
[tex]f = 7.27 \times 10^{-10}[/tex]
Explanation:
As we know that moles is defined as
[tex]n =\frac{mass}{molar mass}[/tex]
[tex]n = \frac{0.0250}{0.026982}[/tex]
[tex]n = 0.93[/tex]
so number of atoms of Al in each sphere is given as
[tex]N = 0.93(6.02 \times 10^{23})[/tex]
[tex]N = 5.58 \times 10^{23}[/tex]
Now number of electrons in each atom is given as
atomic number = number of electrons in each atom = 13
total number of electrons in each sphere is
[tex]N = 13 \times (5.58 \times 10^{23})[/tex]
[tex]N = 7.25 \times 10^{24}[/tex]
Also we know that force of attraction between them is given as
[tex]F= \frac{kq_1q_2}{r^2}[/tex]
[tex]1.00 \times 10^4 = \frac{(9\times 10^9)q^2}{0.80^2}[/tex]
[tex]q = 8.4 \times 10^{-4} C[/tex]
now we have
[tex]q = Ne[/tex]
[tex]8.4 \times 10^{-4} = N(1.6 \times 10^{-19}[/tex]
[tex]N = \frac{(8.4 \times 10^{-4})}{1.6 \times 10^{-19}}[/tex]
[tex]N = 5.27 \times 10^{15}[/tex]
Fraction of electrons transferred is given as
[tex]f = \frac{5.27 \times 10^{15}}{7.25 \times 10^{24}}[/tex]
[tex]f = 7.27 \times 10^{-10}[/tex]
