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Land west of the San Andreas fault in southern California is moving at an average velocity of about 6 cm/y northwest relative to land east of the fault. Los Angeles is west of the fault and may thus someday be at the same latitude as San Francisco, which is east of the fault. How far in the future will this occur if the displacement to be made is 590 km northwest, assuming the motion remains constant?

Respuesta :

Answer:

9833333.33 years

Explanation:

Speed of the land = 6 cm/y = v

Convert the speed to km/y

1 km = 10000 m

⇒1 m = 1/10000 km

⇒1 m = 10⁻⁵ cm

So,

6 cm/y = 6×10⁻⁵ km/y

Distance the land will travel = 590 km = s

Time taken

[tex]t=\frac{s}{v}\\\Rightarrow t=\frac{590}{6\times 10^{-5}}\\\Rightarrow t=9833333.33\ years[/tex]

∴ Time taken by the land to move 590 km is 9833333.33 years.

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