Respuesta :
Answer:
a) List is given in explanation
b) 1/10 or 0.1
Step-by-step explanation:
List of all the courses is:
- EPR 622
- EPR 664
- EPR 602
- EPR 652
- EPR 684
Part a) List all possible two-course selections
We need to list out all the possible two-course selections from the list of 5 available courses. Selecting 2 courses out of 5 means: forming combinations of 2 courses out of 5 courses. So using combinations we can calculate how many selections will be possible. This would be equal to 5C2. The formula of combinations is:
[tex]^{n}C_{r}=\frac{n!}{r!(n-r)!}[/tex]
For, for our case, the formula will be:
[tex]^{5}C_{2}=\frac{5!}{2!(5-2)!}=10[/tex]
This means, 10 possible two-course selections are possible. These selections are listed below:
- EPR 622 and EPR 664
- EPR 622 and EPR 602
- EPR 622 and EPR 652
- EPR 622 and EPR 684
- EPR 664 and EPR 602
- EPR 664 and EPR 652
- EPR 664 and EPR 684
- EPR 602 and EPR 652
- EPR 602 and EPR 684
- EPR 652 and EPR 684
This is the list of all possible two-course selections from the available 5 courses.
Part b) Likelihood that EPR 602 and EPR 684 will be selected
From the above list we can observe that there are total 10 possible options to select from and only one way of selecting EPR 602 and EPR 684.
Likelihood or Probability is defined as ratio of desired outcomes to total possible number of outcomes. So, desired outcome is 1 i.e. selecting EPR 602 and EPR 684, while, total possible outcomes are all the possible 2 course selections which are listed above. Hence, total number of possible outcomes is 10.
Therefore, likelihood of selecting EPR 602 and EPR 684 is = [tex]\frac{1}{10}=0.1[/tex]