Answer:
Acceleration, [tex]a=9.91\times 10^{15}\ m/s^2[/tex]
Explanation:
It is given that,
Separation between the protons, [tex]r=3.73\ nm=3.73\times 10^{-9}\ m[/tex]
Charge on protons, [tex]q=1.6\times 10^{-19}\ C[/tex]
Mass of protons, [tex]m=1.67\times 10^{-27}\ kg[/tex]
We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :
[tex]ma=\dfrac{kq^2}{r^2}[/tex]
[tex]a=\dfrac{kq^2}{mr^2}[/tex]
[tex]a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}[/tex]
[tex]a=9.91\times 10^{15}\ m/s^2[/tex]
So, the acceleration of two isolated protons is [tex]9.91\times 10^{15}\ m/s^2[/tex]. Hence, this is the required solution.
