Answer: The ratio of the mass ratio of S to O in SO to the mass ratio of S to O in [tex]SO_2[/tex] is 2.
Explanation:
We are given:
Mass of sulfur = 32 grams
Mass of oxygen = 16 grams
A chemical compound having a chemical formula of SO
Mass of Sulfur in SO = 32 g
Mass of Oxygen in SO = 16 g
Mass ratio of Sulfur to oxygen in SO = [tex]\frac{\text{Mass of sulfur}}{\text{Mass of oxygen}}=\frac{32g}{16g}=2[/tex] .....(1)
A chemical compound having a chemical formula of [tex]SO_2[/tex]
Mass of Sulfur in [tex]SO_2[/tex] = 32 g
Mass of Oxygen in [tex]SO_2[/tex] = (2 × 16) = 32 g
Mass ratio of Sulfur to oxygen in [tex]SO_2[/tex] = [tex]\frac{\text{Mass of sulfur}}{\text{Mass of oxygen}}=\frac{32g}{32g}=1[/tex] .....(2)
Taking ratio of 1 and 2, we get:
[tex]\frac{\text{Mass ratio of Sulfur to oxygen in SO}}{\text{Mass ratio of Sulfur to oxygen in }SO_2}=\frac{2}{1}=2[/tex]
Hence, the ratio of the mass ratio of S to O in SO to the mass ratio of S to O in [tex]SO_2[/tex] is 2.