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What is the change in length of a 1400. m steel, (12x10^-6)/(C0) , pipe for a temperature change of 250.0 degrees Celsius? Remember to include your data, equation, and work when solving this problem.

Respuesta :

Answer:

[tex]\Delta L = 4.2 m[/tex]

Explanation:

As per the formula of thermal expansion we know that

[tex]L = L_o(1 + \alpha\Delta T)[/tex]

so here we will have

[tex]L_o = 1400 m[/tex]

[tex]\alpha = 12 \times 10^{-6} per ^oC[/tex]

[tex]\Delta T = 250 degree C[/tex]

so here change in the length of the rod is given as

[tex]\Delta L = L - L_o[/tex]

[tex]\Delta L = L_o \alpha \Delta T[/tex]

[tex]\Delta L = 1400 (12 \times 10^{-6})(250)[/tex]

[tex]\Delta L = 4.2 m[/tex]

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