savpetbuddy
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A car traveling north slows down from 40 m/s to rest in a distance of 100 m. What was the magnitude of its average acceleration in m/s^2? and what direction of the car or is there not enough information?

Respuesta :

MathPhys

Answer:

8 m/s² south

Explanation:

Given:

v₀ = 40 m/s

v = 0 m/s

Δx = 100 m

Find: a

v² = v₀² + 2a (x − x₀)

0² = 40² + 2a (100)

a = -8

The acceleration is 8 m/s² south.