Answer:
The resistivity is 1.31 Ωm
Explanation:
Diameter = 1.5 mm
Potential difference = 8.9 V
Current = 240 μA
length = 5.0 cm
We need to calculate the resistivity
Using ohm's law
[tex]V= I\times R[/tex]
We know that,
Formula of resistance
[tex]R = \dfrac{\rho l}{A}[/tex]
Put the value of R in ohm's law
[tex]V=I\times\dfrac{\rho l}{A}[/tex]
Where, [tex]\rho[/tex] = resistivity
A = area
I = length
Put the value into the formula
[tex]8.9=240\times10^{-6}\times\dfrac{\rho\times5.0\times10^{-2}}{\pi\times(0.75\times10^{-3})^2}[/tex]
[tex]\rho=\dfrac{8.9\times\pi\times(0.75\times10^{-3})^2}{240\times10^{-6}\times5.0\times10^{-2}}[/tex]
[tex]\rho=1.31\ \Omega m[/tex]
Hence, The resistivity is 1.31 Ωm
The resistivity is 1.31 Ωm.
This is a property which helps to measure how a material strongly resists electric current.
Parameters
Diameter = 1.5 mm
Potential difference = 8.9 V
Current = 240 μA
Length = 5.0 cm
V = IR
Resistance(R) = ρl/A
V = I × ρl/A
where Where, ρ = resistivity, A = area and I = length
Substitute the values into the equation
8.9 = 240× 10⁻⁶ ₓ ρₓ 5 ₓ 10⁻² / (π ₓ ((0.75 ₓ 10⁻³))²
Resistivity is 1.31 Ωm
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