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If the frog lands with a velocity equal to its average velocity and comes to a full stop 0.25s later, what is the frog’s average acceleration?

Respuesta :

carlosfuentest

Answer:

Average accelation = -4V

Explanation:

[tex]a=\frac{V-V0}{t}[/tex]

V=0 m/s (because the frog stopped)

V0 = V (average velocity)

t= 0,25 s

So;

[tex]a=\frac{V-V0}{t}=\frac{0-V}{0.25}=-4V[/tex]

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