Answer: Option (d) is the correct answer.
Explanation:
Converting Fahrenheit into kelvin as follows.
[tex]\frac{5}{9} \times (^{o}F - 32) + 273.15[/tex]
So, [tex]246^{o}F[/tex] will be converted into kelvin as follows.
[tex]\frac{5}{9} \times (246^{o}F - 32) + 273.15[/tex]
= 392.039 K
Also, [tex]832^{o}F[/tex] will be converted into kelvin as follows.
[tex]\frac{5}{9} \times (832^{o}F - 32) + 273.15[/tex]
= 717.594 K
As 13 K is the temperature at night time. So, it means sulfur will exist as a solid at this time because melting point of sulfur is 392.039 K.
Whereas 683 K is the temperature during day time. Hence, it means sulfur will exist in liquid state because its boiling point is 717.594 K.
Thus, we can conclude that on mercury, sulfur exists as both a liquid and a solid.
